An ideal gas has specific heat capacity at constant pressure 11 10 R . If one mole of this ideal gas at 125^ C does 83 ~J of work adiabatically, then the final temperature of the gas would be (Universal gas constant, R=8.3 ~J ~K ⁻¹ ~mol ⁻¹ )

Step-by-step solution

Work done by gas in adiabatic process, W=+83 ~J As in adiabatic process, Q=0 , By first law of thermodynamics, Q= U+ W so change in internal energy of gas, U=-83 ~J Also, U=n C_V T=83 Here, n=1 mole specific heat at constant volume C_V=C_p-R C_V= 11 10 R-R= 1 10 R aligned & so, -83=1 1 10 R (T_f-125 ) & T_f-125= -830 8.3 =-100 aligned or T_f=125-100=25^ C