A Carnot engine operates between a source and a sink. The efficiency of the engine is 40 % and the temperature of the sink is 27 ° C . If the efficiency is to be increased to 50 % then the temperature of the source must the increased by

Step-by-step solution

Initial efficiency of the engine is 40 % . Therefore, 40 100 = 1 - T sin k T s o u r c e ⇒ 0 . 4 = 1 - 27 + 273 T s o u r c e ⇒ T s o u r c e = 500   K Efficiency in second case of the engine is 50 % . Therefore, 50 100 = 1 - T sin k T s o u r c e ⇒ 0 . 5 = 1 - 27 + 273 T s o u r c e ⇒ T s o u r c e = 600   K So clearly, the increase in temperature will be of 100   K