AP EAMCET202125 Aug 2021Evening ShiftPhysicsThermodynamicsActual
A Carnot engine having an efficiency 1/5 as a heat engine, is used as a refrigerator. If the work done on the system is 50 J, then the amount of energy absorbed from the reservoir at lower temperature is
Options
- A90 J
- B99 J
- C200 J
- D1 J
Correct answer
C. 200 J
Step-by-step solution
Efficiency of Carnot engine, = 1 5 Work done on the system, W = 50 J Coefficient of performance of a refrigerator, aligned & = 1- & = 1- 1 5 1 5 = 4 5 5 1 =4 aligned aligned & Also, = Heat absorbed from reservoir Work done & = Q 50 & 4 50=Q & Q=200 ~J & aligned