The efficiency of an ideal Carnot engine working between temperatures T₁ and T₂ is 1 / 3 . If the temperature of the sink is reduced by 40 % , then its efficiency will be

Step-by-step solution

Efficiency of Carnot engine, = 1 3 But =1- T₂ T₁ where, T₁= and temperature of fource T₂= temperature of sink. 1 3 =1- T₂ T₁ T₂ T₁ =1- 1 3 T₂ T₁ = 2 3 When temperature of sink is reduced by 40 % , then its new temperature, T₂^ =T₂-40 % of T₂ =T₂-0.4 T₂ T₂^ =0.6 T₂ Now, efficiency of Carnot's engine aligned ^ & = (1- T₂^ T₁ ) 100= (1-0.6 T₂ T₁ ) 100 & = (1-0.6 2 3 ) 100=0.6 100=60 % aligned