A Carnot engine takes 3 10^6 calories of heat from reservoir at 627^ C and gives it to a sink at 27^ C . The work done by the engine is

Step-by-step solution

Heat taken by Carnot engine, Q=3 10^6 cal =4.2 3 10^6 ~J Temperature of reservoir (source) T₁=(627+273) K =900 ~K Temperature of sink, T₂=(27+273) K =300 ~K We know that, efficiency of Carnot engine, = W Q = l - T₂ T₁ aligned & W Q =1- T₂ T₁ & W 42 3 10^6 =1- 300 900 & W 42 3 10^6 = 2 3 & W= 2 3 4.2 3 10^6=8.4 10^6 ~J aligned