Freezing compartment of a refrigerator is at 0 ° C and room temperature is 27 . 3 ° C . Work done by the refrigerator to freeze 1 g of water at 0 ° C is L ice = 80 cal g - 1

Step-by-step solution

The energy released by refrigerator, Q 2 = m L = 1 × 80 × 4 . 2   J Recall the formula of the coefficient of performance, K = Q 2 W = T 2 T 1 - T 2 ⇒ 80 × 4 . 2 W = 273 27 . 3 ⇒ W = 80 × 4 . 2 10 = 33 . 6   J