An ideal monoatomic gas is carried along the cycle A B C D A as shown in the figure. The total heat absorbed during this process is

Step-by-step solution

Heat absorbed means heat is extracted from source, i.e.Q must be positive. This occurs along path aligned A B C . & & Heat added = Q_ A B C = U_ A B C + W_ A B C = & n C_V (T_C-T_A )+3 p₀ (2 V₀-V₀ ) = & n 3 2 R (T_C-T_A )+3 p₀ V₀= 3 2 (n R T_C-n R T_A )+3 p₀ V₀ = & 3 2 (p_C V_C-p_A V_A )+3 p₀ V₀ = & 3 2 (3 p₀ 2 V₀-p₀ V₀ )+3 p₀ V₀ = & 3 2 5 p₀ V₀+3 p₀ V₀= 21 2 p₀ V₀=10.5 p₀ V₀ aligned