Freezing compartment of a refrigerator is at 0^ C and room temperature is 27.3^ C . Work done by the refrigerator to freeze 1 ~g of water at 0^ C is (L_ ice =80 cal g ⁻¹ )

Step-by-step solution

Coefficient of performance of refrigerator is aligned & = T₂ T₁-T₂ T₂ & =0^ C =0+273=273 ~K T₁ & =27.3^ C 300 ~K & = 273 300-273 10 aligned Now, if Q₂ is heat extracted and W is work performed them, = Q₂ W or W= Q₂ where, Q₂= heat extracted from 1 g of water to make it ice =m L₁=80 cal =80 4.2 ~J =336 ~J So, W=336 / 10=33.6 ~J