One mole of a gas expands such that its volume ' V ' changes with absolute temperature ' T ' in accordance with the relation V=K T^2 where ' K ' is a constant. If the temperature of the gas changes by 60^ C , then work done by the gas is (

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One mole of a gas expands such that its volume ' V ' changes with absolute temperature ' T ' in accordance with the relation V=K T^2 where ' K ' is a constant. If the temperature of the gas changes by 60^ C , then work done by the gas is ( R is universal gas constant).

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Correct answer: D. 120 R

V =K T^2 d V=2 K T d T So, W= P d V=R T v d V =R T K T^2 2 K T=2 R ₀⁶⁰ d T=120 R

One mole of a gas expands such that its volume ' V ' changes with absolute temperature ' T ' in accordance with the relation V=K T^2 where ' K ' is a constant. If the temperature of the gas changes by 60^ C , then work done by the gas is ( R is universal gas constant).

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