When the absolute temperature of the source of a Carnot heat engine is increased by 25 % , its efficiency increases by 80 % . The new efficiency of the engine is

Step-by-step solution

According to the question, initially aligned & = 100-T₂ 100 & = + 80 100 =1.8 = 125-T₂ 125 & ^ = 100-T₂ 100 125 125-T₂ & 1 18 = 100-T₂ 100 125 125-T₂ & or, 5 9 = 100-T₂ 100 5 (125-T₂ ) & or, 9 (100- T ₂ )=500-4 ~T ₂ & or, 900-9 ~T ₂=500-4 ~T ₂ & or, 400=5 ~T ₂ & or, T ₂= 400 5 =80 aligned The new efficiency, aligned & ^ =1- T₂ T₁ =1- 80 125 & 125-80 125 = 45 125 = 45 125 100=36 % aligned