AP EAMCET202420 May 2024Morning ShiftPhysicsWave OpticsActual
In Young's double slit experiment, two slits are placed 2 mm from each other. Interference pattern is observed on a screen placed 2 m from the plane of the slits. Then the fringe width for a light of wavelength 400 nm is
Options
- A0.4 10⁻⁶ ~m
- B4 10⁻⁶ ~m
- C0.4 10⁻³ ~m
- D400 m
Correct answer
C. 0.4 10⁻³ ~m
Step-by-step solution
In YDSE, d =2 ~mm =2 10⁻⁵ ~m , D =2 ~m , =400 ~nm Fringe width, = D d = 400 10⁻⁹ 2 2 10⁻³ =0.4 10⁻³ ~m