AP EAMCET202419 May 2024Evening ShiftPhysicsWave OpticsActual
In Young's double slit experiment, the intensity at a point where the path difference is 6 ( 1 being the wavelength of the light used) is I . If I₀ denotes the maximum intensity. I I ₀ , is equal to
Options
- A1 2
- B3 2
- C1 2
- D3 4
Correct answer
D. 3 4
Step-by-step solution
In YDSE, x= 6 , I ₁= I ₂ Phase difference, = 2 x= 2 6 = 3 aligned & I = I ₁+ I ₂+2 I ₁ I ₂ & = I ₁+ I ₁+2 I ₁ 3 =3 I ₁ & I ₀= ( I ₁ + I ₂ )^2= (2 I ₁ )^2=4 I ₁ & I I ₀ = 3 I ₁ 4 I ₁ = 3 4 aligned