AP EAMCET20225 Jul 2022Morning ShiftPhysicsWave OpticsActual
In Young's double slit experiment the slits are 3 ~mm apart and are illuminated by light of two wavelengths 3750 Å and 7500 Å . The screen is placed at 4 ~m from the slits. The minimum distance from the common central bright fringe on the screen at which the bright fringe of one interference pattern due to one wavelength coincide with the bright fringe of the other is
Options
- A2 ~mm
- B3 ~mm
- C1 ~mm
- D8 ~mm
Correct answer
C. 1 ~mm
Step-by-step solution
Given, ₁=3750 Å aligned ₂ & =7500 Å D & =4 ~m d & =3 ~mm =3 10⁻³ ~m aligned since, ₁ ₂ = 3750 7500 = 1 2 We know that, n₁ ₁=n₂ ₂ n₂ n₁ = ₁ ₂ = 1 2 Required minimum distance, x= n₁ ₁ D d aligned & = 2 3750 10⁻¹⁰ 4 3 10⁻³ = 3 10^4 10⁻¹⁰ 3 10⁻³ & =10⁻³ ~m =1 ~mm aligned