If the ratio of amplitudes of two interfering waves is 4: 3 , then the ratio of maximum and minimum intensity is

Step-by-step solution

Given, the ratio of amplitudes of two interfering waves is 4: 3 i.e A₁ A₂ = 4 3 ...(i) We know that, intensity of wave is proportional to square of amplitude. I_ I_ = ( A_ A_ )^2 , where maximum and minimum amplitudes are A_ max =A₁+A₂ and A_ =A₁-A₂ Substituting the values, we get I_ I_ = ( A₁+A₂ A₁-A₂ )^2 Multiplying and dividing by A₂^2 in RHS, we get. I_ I_ = ( A₁ A₂ +1 A₁ A₂ -1 )^2= ( 4 3 +1 4 3 -1 )^2= ( 7 1 )^2= 49 1