In a diffraction pattern due to a single slit of width ' a ' , the first minimum is observed at an angle 30 ° when light of wavelength 500 nm is incident on the slit. The first secondary maximum is observed at an angle of

Step-by-step solution

Given that for slit of width a   the first minimum form at θ = 30 ° ,   the wavelength of light is 500   nm Using Bragg's law of diffraction, n λ = a sin θ ,   here n   is the whole number and for the first minimum n = 1   ⇒ 1 λ = a sin 30 ° ⇒ a = 2 λ                               For the first secondary maximum, n + 1 2 λ = a sin θ '   where n =