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AP EAMCET2006PhysicsWave Optics

In Young's double slit experiment, first slit has width four times the width of the second slit. the ratio of the maximum intensity to the minimum intensity in the interference fringe system is :

Options

  1. A2: 1
  2. B4: 1
  3. C9: 1
  4. D8: 1

Correct answer

C. 9: 1

Step-by-step solution

Let intensity of light coming from each slit of a coherent source is I . As first slit has width 4 times the width of the second slit, so I₁=4 I and I₂=I I_ I_ = ( I₁ + I₂ )^2 ( I₁ - I₂ )^2 = ( 4 I + I )^2 ( 4 I - I )^2 = 9 1

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