What is the phase difference between two particles (25 ~m ) apart in a wave represented by equation (y=0.03 ( [2 t-0.01 x]) s ) travelling in a medium?

Step-by-step solution

Equation of wave is given as (y=0.03 ( [2 t-0.01 x]) ) Path difference, ( x=25 ~m ) Comparing the wave equation by ( aligned y & =A ( t-k x) , we get k=0.01 2 & =0.01 = 2 0.01 =2 10^2 ~m aligned ) ( ) Phase difference, ( = 2 x= 2 2 10^2 25= 4 )