AP EAMCET202017 Sep 2020Morning ShiftPhysicsWaves and SoundActual
On producing the waves of frequency (1000 ~Hz ) in a Kundt's tube, the total distance between 6 successive nodes is (85 ~cm ). Then, the speed of sound in the gas filled in the tube is
Options
- A(330 ~ms ⁻¹ )
- B(340 ~ms ⁻¹ )
- C(350 ~ms ⁻¹ )
- D(300 ~ms ⁻¹ )
Correct answer
B. (340 ~ms ⁻¹ )
Step-by-step solution
Frequency, (f=1000 ~Hz ) Total distance between 6 successive nodes (d=85 ~cm =0.85 ~m ) Since, distance between 6 successive nodes is equivalent to (2 + 2 = 5 2 ) ( d= 5 2 =0.85 = 0.85 2 5 =0.34 ~m ) ( ) Speed of sound in tube, (v=f =1000 0.34=340 ~ms ⁻¹ )