A open pipe of length l is vibrating in 3 rd overtone with maximum amplitude A . The amplitude at a distance of l 16 from any open end is

Step-by-step solution

For open organ pipe, wavelength of n^ th overtone aligned & _n= 2 l n+1 (n=3) & = 2 l 4 = l 2 aligned As pipe is open, so antinode (maximum amplitude) will form at open ends. At l=0 , amplitude =A At l 16 or 8 distance, amplitude, R=A where, = phase angle. gathered = 2 8 = 4 =45^ R=A 45^ R= A 2 gathered