A closed pipe is suddenly opened and changed to an open pipe of same length. The fundamental frequency of the resulting open pipe is less than that of 3rd harmonic of the earlier closed pipe by 55 ~Hz . Then, the value of fundamental freque

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A closed pipe is suddenly opened and changed to an open pipe of same length. The fundamental frequency of the resulting open pipe is less than that of 3rd harmonic of the earlier closed pipe by 55 ~Hz . Then, the value of fundamental frequency of the closed pipe is

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Correct answer: C. 55 ~Hz

Frequency of first mode of vibration n₁= 3 v 4 / (closed pipe) and frequency of first mode of vibration n₂= v 2 l (open pipe) According to the question, n₁-n₂= 3 v 4 l - v 2 l =55 So 3 v-2 v 4 ! =55 v 4 l =55 ~Hz

A closed pipe is suddenly opened and changed to an open pipe of same length. The fundamental frequency of the resulting open pipe is less than that of 3rd harmonic of the earlier closed pipe by 55 ~Hz . Then, the value of fundamental frequency of the closed pipe is

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