AP EAMCET2005PhysicsWaves and Sound
A transverse wave propagating on a stretched string of linear density 3 10⁻⁴ ~kg ~m ⁻¹ is represented by the equation y=0.2 (15 x+60 t) where x is in metres and t is in seconds. The tension in the string (in newton) is
Options
- A0.24
- B0.48
- C1.20
- D1.80
Correct answer
B. 0.48
Step-by-step solution
Equation of wave, y=0.2 (1.5 x+60 t) Comparing with standard equation, aligned & y=A (k x+ t) & k=1.5, =60 rad / s aligned Velocity of wave, v= k = 60 1.5 =40 ~m / s Velocity of wave in a stretched string, v= T m where m= linear density T= tension in the string So, aligned T & =v^2 m & =(40)^2 3 10⁻⁴=0.48 aligned