AP EAMCET202422 May 2024Evening ShiftPhysicsWork, Power and EnergyActual
A force of (4 i+2 j+k) N is acting on a particle of mass 2 kg displaces the particle from a position of (2 i +2 j + k ) m to a position of (4 i +3 j +2 k ) m . The work done by the force on the particle in joules is
Options
- A21 J
- B11 J
- C14 J
- D18 J
Correct answer
B. 11 J
Step-by-step solution
F =(4 i +2 j + k ) N , m =2 ~kg r₁ =(2 i +2 j + k ) m, r₂ =(4 i +3 j +2 k ) m aligned & Work done, W= F S = F ( r₂ - r₁ ) & =(4 i +2 j + k ) (2 i + j + k ) & =4 2+2 1+1 1=11 ~J aligned