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AP EAMCET202422 May 2024Evening ShiftPhysicsWork, Power and EnergyActual

A force of (4 i+2 j+k) N is acting on a particle of mass 2 kg displaces the particle from a position of (2 i +2 j + k ) m to a position of (4 i +3 j +2 k ) m . The work done by the force on the particle in joules is

Options

  1. A21 J
  2. B11 J
  3. C14 J
  4. D18 J

Correct answer

B. 11 J

Step-by-step solution

F =(4 i +2 j + k ) N , m =2 ~kg r₁ =(2 i +2 j + k ) m, r₂ =(4 i +3 j +2 k ) m aligned & Work done, W= F S = F ( r₂ - r₁ ) & =(4 i +2 j + k ) (2 i + j + k ) & =4 2+2 1+1 1=11 ~J aligned

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