A force of (6 x^2-4 x+3 ) N acts on a body of mass 0.75 kg and displaces it from x=2 ~m to x=5 ~m . The work done by the force is

Step-by-step solution

F= (6 x^2-4 x+3 ) N, m=0.75 ~kg , x₁=2 m, x₂=5 ~m Work done, W= _ x ₁ ^ x ₂ F d x= ₂^5 (6 x ^2-4 x +3 ) dx = [6 x^3 3 -4 x^2 2 +3 x ]₂^5=201 J