A ball is dropped from some height and after first collision with the ground if it reaches 3 4 ^ th of its original height, then the % loss of its energy.

Step-by-step solution

Let a ball is dropped from height h then initial potential energy U_i=m g h Final height = 3 4 h then final potential energy, U_f= 3 4 mgh The percentage loss of its energy | U_f-U_j U_j | 100= | 3 4 m g h-m g h m g h | 100 % = 1 4 100=25 %