AP EAMCET202318 May 2023Evening ShiftPhysicsWork, Power and EnergyActual
A spring has a spring constant 200 Nm ⁻¹ . If it is stretched by 1 ~cm then the potential energy stored in it is
Options
- A100 ~J
- B0.01 ~J
- C10 ~J
- D1 ~J
Correct answer
B. 0.01 ~J
Step-by-step solution
Spring constant, k =200 ~N / m Stretched length, x=1 ~cm =0.01 ~m Potential energy stored is given as: aligned & V = 1 2 kx ^2= 1 2 200 0.01 0.01 & ~V =0.01 ~J aligned