A ball of mass 10 ~g is allowed to fall down from 10 m height. After collision with the ground if 50 % of its energy is lost, then the height reached by the ball is

Step-by-step solution

Mass of ball, m =10 ~g =10 10⁻³ ~kg Height, h =10 ~m Apply the conservation of energy potential energy = kinetic energy K . E = mgh =10 mg ...(i) K . E ^ =50 % ~K . E Use equation (1), we have =5 10 mg aligned & =5 mg & P E ^ = K E ^ = mgh 5 mg = mgh & h =5 ~m . aligned The height reached by the ball is 5 ~m .