AP EAMCET20228 Jul 2022Morning ShiftPhysicsWork, Power and EnergyActual
A 1 ~kg box placed at the origin starts sliding along x -axis under the action of a force F =F i . Its acceleration as a function of x is given by a(x)= . x where =5 ~s ⁻² . The work done by F in moving the box from x =2 ~cm to x =5 ~cm in joule is
Options
- A52.5 10⁻⁴
- B105.5 10⁻⁴
- C17.0 10⁻⁴
- D34.0 10⁻⁴
Correct answer
A. 52.5 10⁻⁴
Step-by-step solution
Work done = Fdx = _ 0.02 ^ 0.05 ~m ( x ) dx aligned & = 1 5 2 [ x ^2 ]_ 0.02 ^ 0.05 & = 5 2 [25 10⁻⁴-4 10⁻⁴ ] & = 5 2 21 10⁻⁴ & =52.5 10⁻⁴ Joule. aligned