A block of mass 50 ~kg is pulled with a constant speed of 4 ~ms ⁻¹ across a horizontal floor by an applied force of 500 ~N directed 30^ above the horizontal. The rate at which the force does work on the block in watt is

Step-by-step solution

Mass of block, m=50 ~kg , speed of block, v=4 ~ms ⁻¹ , F=500 ~N and =30^ , The rate at which the force does work on the block is equal to power which is given as P= Force in the horizontal direction velocity aligned & =500 30^ v & =500 3 2 4=100 3 & =100 1.732=1732 ~W aligned