A cyclist comes to a skidding stop in (10 ~m ). During this process, the force on the cycle due to the road is (200 ~N ) and is directly opposite to the motion. How much work does the road do on the cycle?

Step-by-step solution

Displacement travelled by cyclist to reach skidding stop, (s=10 ~m ) Force on the cyclist due to road, (F=200 ~N ) Since, force is applied directly opposite to motion (or displacement), hence ( =180^ ) ( ) Work done by the road on the cycle (W=F s =200 10 180^ =-2000 ~J )