A wheel which is initially at rest is subjected to a constant angular acceleration about its axis. It rotates through an angle of 15^ in time t sec. The increase in angle through which it rotates in the next 2 t sec is

Step-by-step solution

If angular acceleration is constant, we have = ₀ t+ 1 2 t^2 The given =15^ ₀=0 For the first conditions (time =t sec ) aligned 15^ & =0+ 1 2 t^2 15^ & = 1 2 t^2 aligned For the second conditions (time =3 t sec ) ₁= 1 2 (3 t)^2= 1 2 ( ) 9 t^2 So, aligned & = ₁- 1 2 t^2 & =9 1 2 t^2- 1 2 t^2 & =8 1 2 t^2 & =8 15^ =120^ aligned (from Eq. (i))