A force applied by an engine on a train of mass 2.05 10^6 ~kg changes its velocity from 5 ~m / s to 25 ~m / s in 5 minutes. The power of the engine is

Step-by-step solution

aligned m=2.05 & 10^6 ~kg , v₁=5 ~m / s v₂ & =25 ~m / s , t=5 ~min & =5 60=300 sec Power & = W t = change in KE t & = 1 2 m (v₂^2-v₁^2 ) 300 & = 1 2 2.05 10^6 [(25)^2-(5)^2 ] 300 & = 1 2 2.05 10^6 600 300 & =2.05 10^6 ~W & =2.05 MW aligned