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BITSAT 2020
Exam
BITSAT
Year
2020
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

BITSAT 2020 · Chemistry · Carboxylic Acid Derivatives

Which of the following reactions will not give N, N -dimethyl...

Which of the following reactions will not give N,N\mathrm{N}, \mathrm{N} -dimethyl benzamide?Which of the following reactions will not give N, N -dimethyl benzamide?Which of the following reactions will not give N, N -dimethyl benzamide?Which of the following reactions will not give N, N -dimethyl benzamide?Which of the following reactions will not give N, N -dimethyl benzamide?

Options

  1. ALet x_1 be a positive real number and for every integer n ≥ 1 let x_ n+1 =1+x_1 x_2 x_ n-1 x_n . If x_5=43 , what is
  2. BLet x_1 be a positive real number and for every integer n ≥ 1 let x_ n+1 =1+x_1 x_2 x_ n-1 x_n . If x_5=43 , what is
  3. CLet x_1 be a positive real number and for every integer n ≥ 1 let x_ n+1 =1+x_1 x_2 x_ n-1 x_n . If x_5=43 , what is
  4. DLet x_1 be a positive real number and for every integer n ≥ 1 let x_ n+1 =1+x_1 x_2 x_ n-1 x_n . If x_5=43 , what is

Correct answer

B. Let x_1 be a positive real number and for every integer n ≥ 1 let x_ n+1 =1+x_1 x_2 x_ n-1 x_n . If x_5=43 , what is

Step-by-step solution

(a) C6H5COOC2H5+(CH3)2NH→C6H5CON(CH3)2+C2H5OH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOC}_{2} \mathrm{H}_{5}+\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH} \rightarrow\mathrm{C}_{6} \mathrm{H}_{5}\mathrm{CON}\left(\mathrm{CH}_{3}\right)_{2}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} (b) C6H5CONH2+CH3MgI→C6H5CONHMgI+CH4\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CONH}_{2}+\mathrm{CH}_{3} \mathrm{MgI}\rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CONH} \mathrm{MgI}+\mathrm{CH}_{4} (c) C6H5COCl+(CH3)2NH→C6H5CON(CH3)2+HCl\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl}+\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH} \rightarrow\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CON}\left(\mathrm{CH}_{3}\right)_{2}+\mathrm{HCl} (d) C6H5CO.O.COC6H5+(CH3)2NH→C6H5CON(CH3)2+C6H5COOH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}. \mathrm{O}. \mathrm{COC}_{6} \mathrm{H}_{5}+\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CON}\left(\mathrm{CH}_{3}\right)_{2}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}
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