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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Chemistry
Chapter
General Organic Chemistry

BITSAT 2013 · Chemistry · General Organic Chemistry

The number of enantiomers of the compound CH_ 3 CHBrCHBrCOOH is

The number of enantiomers of the compound CH3CHBrCHBrCOOH\mathrm{CH}_{3} \mathrm{CHBrCHBrCOOH} is

Options

  1. A0
  2. B1
  3. C3
  4. D4

Correct answer

D. 4

Step-by-step solution

The structure CH3∗CHBrC∗HBrCOOH\mathrm{CH}_{3}{ }^{*} \mathrm{CH} \mathrm{Br} \mathrm{C}^{*} \mathrm{H} \mathrm{Br} \mathrm{COOH} has two different chiral carbon atoms, hence number of enantiomers (optically active forms) is 2n=22=42^{n}=2^{2}=4
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