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BITSAT 2017
Exam
BITSAT
Year
2017
Subject
Chemistry
Chapter
p Block Elements (Group 15, 16, 17 & 18)

BITSAT 2017 · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

When aqueous solutions of borax is acidified with HCl , we get

When aqueous solutions of borax is acidified with HClHCl, we get

Options

  1. AB2H6{B}_{2}{H}_{6}
  2. BH3BO3{H}_{3}{BO}_{3}
  3. CB2O3{B}_{2}{O}_{3}
  4. DAll of these

Correct answer

B. H3BO3{H}_{3}{BO}_{3}

Step-by-step solution

When aqueous solution of borax (Na2B4O7)\left({Na}_{2}{B}_{4}{O}_{7}\right) is acidified
with HClHCl, we get H3BO3andNaCl{H}_{3}{BO}_{3} and NaCl as follows

Na2B4O7Borox+2HCl+5H2O⟶2NaCl+4H3BO3Boricacid\mathop{{Na}_{2}{B}_{4}{O}_{7}}_{Borox} + 2HCl + 5{H}_{2}O ⟶ 2NaCl + \mathop{4{H}_{3}{BO}_{3}}_{Boricacid}

Boric acid is not a proticacid it does not give H+H^{+} ion accepts a pair of electrons and acts as a Lewis acid.

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