Adsorption of a gas follows Freundlich adsorption isotherm. $x$ is the mass of the gas adsorbed on mass $m$ of the adsorbent. The plot of $\frac{x}{m}$ versus $\log p$ is shown in the given graph.
$\frac{x}{m}$ is proportional to :

Question

Adsorption of a gas follows Freundlich adsorption isotherm.

x

is the mass of the gas adsorbed on mass

m

of the adsorbent. The plot of

\frac{x}{m}

versus

\log p

is shown in the given graph. Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the

\frac{x}{m}

is proportional to :

Quantrex Academy · Accepted Answer

Correct answer: A. p^ 2 / 3

According to Freundlich adsorption isotherm (x)/(m) p^ (1)/(n) , (x)/(m)=k p^ (1)/(n) Slope =(2)/(3) (x)/(m)= k+(1)/(n) p Slope =(1)/(n)=(2)/(3)(x)/(m) p^ (2)/(3)

Adsorption of a gas follows Freundlich adsorption isotherm. x is...

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