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BITSAT 2014
Exam
BITSAT
Year
2014
Subject
Mathematics
Chapter
Basics of Mathematics

BITSAT 2014 · Mathematics · Basics of Mathematics

2^ 3 n -7 n-1 is divisible by

23n−7n−12^{3 n}-7 n-1 is divisible by

Options

  1. A64
  2. B36
  3. C49
  4. D25

Correct answer

C. 49

Step-by-step solution

23n−7n−12^{3 n}-7 n-1 \quad Taking n=2;n=2 ;26−7×2−1=64−15=49\begin{array}{l} 2^{6}-7 \times 2-1 \\ =64-15=49 \end{array}Thereforethisisdivisibleby49.Therefore this is divisible by 49.
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