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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Mathematics
Chapter
Basics of Mathematics

BITSAT 2013 · Mathematics · Basics of Mathematics

The set of all real x satisfying the inequality (3-|x|)/(4-|x|) ≥...

The set of all real xx satisfying the inequality 3−∣x∣4−∣x∣≥0,\frac{3-|x|}{4-|x|} \geq 0, is

Options

  1. A[-3,3]∪(−∞,−4)∪(4,∞)\cup(-\infty,-4) \cup(4, \infty)
  2. B(−∞,−4)∪(4,∞)(-\infty,-4) \cup(4, \infty)
  3. C(−∞,−3)∪(4,∞)(-\infty,-3) \cup(4, \infty)
  4. D(−∞,−3)∪(3,∞)(-\infty,-3) \cup(3, \infty)

Correct answer

A. [-3,3]∪(−∞,−4)∪(4,∞)\cup(-\infty,-4) \cup(4, \infty)

Step-by-step solution

Given, 3−∣x∣4−∣x∣≥0⇒3−∣x∣≤0\frac{3-|x|}{4-|x|} \geq 0\Rightarrow 3-|x| \leq 0 and 4−∣x∣<04-|x|< 0 or 3−∣x∣≥03-|x| \geq 0 and 4−∣x∣<0⇒∣x∣≥34-|x|< 0\Rightarrow|x| \geq 3 and ∣x∣>4|x| > 4 or ∣x∣≤3|x| \leq 3 and ∣x∣<4⇒∣x∣>4|x|< 4\Rightarrow|x| > 4 or ∣x∣≤3⇒x∈(−∞,−4)∪[−3,3]∪(4,∞)|x| \leq 3\Rightarrow x \in(-\infty,-4) \cup[-3,3] \cup(4, \infty)
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