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BITSAT2013MathematicsBasics of MathematicsActual

If x satisfies |3 x-2|+|3 x-4|+|3 x-6| 12 , then

Options

  1. A0 x 8 3
  2. Bx 8 3 or -4 3
  3. Cx 0 or x 8 3
  4. Dx 2 only

Correct answer

C. x 0 or x 8 3

Step-by-step solution

Dividing R at 2 3 , 4 3 and 2, analyse 4 cases. When x 2 3 , the inequality becomes 2-3 x+4-3 x+6-3 x 12 implying -9 x 0 x 0 when x 2 the ineqality becomes 3 x-2+3 x-4+3 x-6 12 Implying 9 x 24 x 8 / 3 The inequality in invalid in the other two sections. either x 0 or x 8 / 3

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