Let x and y be two natural numbers such that x y=12(x+y) and x y . Then the total number of pairs (x, y) is

Step-by-step solution

x y-12 x-12 y=0 (x-12)(y-12)=144 Now 144 can be factorised into two factors x and y where x y and the factors are (1,144),(2,72),(3,48),(4,36),(6,24),(8,18) (9,16),(12,12) Thus there are eight solutions.