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BITSAT2019MathematicsDefinite IntegrationActual

Suppose the limit L = lim n → ∞ n ∫ 0 1 1 1 + x 2 n d x exists and is larger than 1 2 , then

Options

  1. A1 2 < L < 2
  2. B2 < L < 3
  3. C3 < L < 4
  4. DL ≥ 4

Correct answer

A. 1 2 < L < 2

Step-by-step solution

We have, L = lim n → ∞ n ∫ 0 1 d x 1 + x 2 n We know that, 1 + x 2 n > 1 + n x 2 ⇒   1 1 + x 2 n < 1 1 + n x 2 ⇒   ∫ 0 1 d x 1 + x 2 n < ∫ 0 1 1 1 + n x 2 d x ⇒   ∫ 0 1 1 1 + x 2 n < 1 n tan - 1 n x 0 1 = 1 n tan - 1 n L = lim n → ∞ n ∫ 0 1 1 1 + x 2 n d x < lim n → ∞ n 1 n tan - 1 n ∴   L = π 2

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