BITSAT 2019
- Exam
- BITSAT
- Year
- 2019
- Subject
- Mathematics
- Chapter
- Definite Integration
BITSAT 2019 · Mathematics · Definite Integration
Suppose the limit L = _ n → ∞ n ∫ _ 0 ^ 1 1 (1 + x^ 2 )n dx exists...
Suppose the limit exists and is larger than , then
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
We have,&
We know that, \left(1 + x^{2}\right)n > 1 + nx^{2}⇒ \dfrac{1}{\left(1 + x^{2}\right)n} < \dfrac{1}{1 + nx^{2}}⇒ {∫}_{0}^{1}\dfrac{dx}{\left(1 + x^{2}\right)n} < {∫}_{0}^{1}\dfrac{1}{1 + nx^{2}}dx⇒ {∫}_{0}^{1}\dfrac{1}{\left(1 + x^{2}\right)n} < \dfrac{1}{n}{\tan^{- 1}\sqrt{n}x}_{0}^{1}= \dfrac{1}{n}\tan^{- 1}\sqrt{n}L = \lim_{n \to \infty}\sqrt{n}{∫}_{0}^{1}\dfrac{1}{\left(1 + x^{2}\right)n}dx < \lim_{n \to \infty}\sqrt{n}\dfrac{1}{n}\tan^{- 1}\sqrt{n}∴ L = \dfrac{π}{2}