Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT 2019
Exam
BITSAT
Year
2019
Subject
Mathematics
Chapter
Definite Integration

BITSAT 2019 · Mathematics · Definite Integration

Suppose the limit L = _ n → ∞ n ∫ _ 0 ^ 1 1 (1 + x^ 2 )n dx exists...

Suppose the limit L=lim⁡n→∞n∫011(1+x2)ndxL = \lim_{n \to \infty}\sqrt{n}{∫}_{0}^{1}\dfrac{1}{\left(1 + x^{2}\right)n}dx exists and is larger than 12\dfrac{1}{2}, then

Options

  1. A12<L<2\dfrac{1}{2} < L < 2
  2. B2<L<32 < L < 3
  3. C3<L<43 < L < 4
  4. DL≥4L \ge 4

Correct answer

A. 12<L<2\dfrac{1}{2} < L < 2

Step-by-step solution

We have,&

L=lim⁡n→∞n∫01dx(1+x2)nL = \lim_{n \to \infty}\sqrt{n}{∫}_{0}^{1}\dfrac{dx}{\left(1 + x^{2}\right)n}

We know that, \left(1 + x^{2}\right)n > 1 + nx^{2}</p><p></p><p>⇒ \dfrac{1}{\left(1 + x^{2}\right)n} < \dfrac{1}{1 + nx^{2}}</p><p></p><p>⇒ {∫}_{0}^{1}\dfrac{dx}{\left(1 + x^{2}\right)n} < {∫}_{0}^{1}\dfrac{1}{1 + nx^{2}}dx</p><p></p><p>⇒ {∫}_{0}^{1}\dfrac{1}{\left(1 + x^{2}\right)n} < \dfrac{1}{n}{\tan^{- 1}\sqrt{n}x}_{0}^{1}</p><p></p><p>= \dfrac{1}{n}\tan^{- 1}\sqrt{n}</p><p></p><p>L = \lim_{n \to \infty}\sqrt{n}{∫}_{0}^{1}\dfrac{1}{\left(1 + x^{2}\right)n}dx < \lim_{n \to \infty}\sqrt{n}\dfrac{1}{n}\tan^{- 1}\sqrt{n}</p><p></p><p>∴ L = \dfrac{π}{2}

Practice Definite Integration on Quantrex Academy →

More from Definite Integration

∫_0^ ∞ (d x)/((x^2+a^2)(x^2+b^2)) is BITSAT 2024The value of definite integral ∫_0^ π / 2 ( x) d x is BITSAT 2024∫_5^9 ( 3 x^2)/( 3 x^2+ (588-84 x+3 x^2)) d x is equal to BITSAT 2024The integral ∫ (x^2(x ^2 x+ x))/((x x+1)^2) d x is equal to BITSAT 2024_ n arrow ∞ ∏_ r=3 ^ ∞ (r^3-8)/(r^3+8) equals to BITSAT 2024∫_0^ (π)/(2) ( ((π)/(4)+x)+ ((3 π)/(4)+x))/( x+ x) d x= BITSAT 2024∫_0^ π / 4 x e^ x d x is equal to BITSAT 2023∫_ -a ^ 4 (x^ 8 -x^ 4 +x^ 2 +1) d x=2 ∫_ 0 ^ 4 (x^ 8 -x^ 4 +x^ 2 +1) d x then a= BITSAT 2021Evaluate: ∫_ 0 ^ π (1)/(5+4 x) d x BITSAT 2021∫_ 0 ^ ∞ dx ( ^ 2 + ^ 2 )( ^ 2 + ^ 2 ) is BITSAT 2020∫_ π / 3 ^ π / 2 x (π[x]-x) dx is equal to BITSAT 2020The value of ∫ _ 0 ^ 1 ^ -1 (1 - x + x^ 2 )dx is BITSAT 2018The expression ∫ _ 0 ^ n [x]dx ∫ _ 0 ^ n \ x\ dx , where [x] and \ x\ are integral and… BITSAT 2017∫_ 0 ^ 10 x^ 10 (10-x)^ 10 +x^ 10 d x is equal to BITSAT 2014Elvaluate ∫_ 0 ^ π / 2 x 1+ ^ 2 x d x BITSAT 2013∫_ 0 ^ π / 2 2^ x 2^ x +2^ x d x equals BITSAT 2012 Full Definite Integration list Definite Integration JEE Maths PYQsJEE Mathematics PYQs All BITSAT PYQs