BITSAT2012MathematicsHyperbolaActual
Find the eccentricity of the conic represented by x²-y²-4 x+4 y+16=0
Options
- A2
- B2
- C2 2
- D3 2
Correct answer
B. 2
Step-by-step solution
We have x²-y²-4 x+4 y+16=0 (x²-4 x )- (y²-4 y )=16 (x²-4 x+4 )- (y²-4 y+4 )=-16 (x-2)²-(y-2)²=-16 (x-2)² 4² - (y-2)² 4² =1 This is rectangular hyperbola, whose eccentricity is always 2 .