A person invites a party of 10 friends at dinner and place so that 4 are on one round table and 6 on the other round table. Total number of ways in which he can arrange the guests is

Step-by-step solution

Total person =10 Two groups are formed containing 4 and 6 persons. Total ways of formation of groups = 10! 4!6! Now, 4 persons can be arranged on round table =(4-1)!=3! and 6 persons can be arranged on round table =(6-1) ! =5! Total ways of arranging the guest = 10! 4!6! 3! 5!= 10! 24