BITSAT2023MathematicsPermutation and CombinationActual
How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions?
Options
- A16
- B36
- C60
- D180
Correct answer
C. 60
Step-by-step solution
X - X - X - X - X . The four digits 3, 3, 5,5 can be arranged at (-) places in 4 ! 2 ! 2 ! =6 ways. The five digits 2,2,8,8,8 can be arranged at (X) places in 5 ! 2 ! 3 ! ways =10 ways Total no. of arrangements =6 10=60 ways