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BITSAT2023MathematicsPermutation and CombinationActual

How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions?

Options

  1. A16
  2. B36
  3. C60
  4. D180

Correct answer

C. 60

Step-by-step solution

X - X - X - X - X . The four digits 3, 3, 5,5 can be arranged at (-) places in 4 ! 2 ! 2 ! =6 ways. The five digits 2,2,8,8,8 can be arranged at (X) places in 5 ! 2 ! 3 ! ways =10 ways Total no. of arrangements =6 10=60 ways

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