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BITSAT 2022
Exam
BITSAT
Year
2022
Subject
Mathematics
Chapter
Permutation and Combination

BITSAT 2022 · Mathematics · Permutation and Combination

The number of different seven-digit numbers that can be written...

The number of different seven-digit numbers that can be written using only the three digit 1 , 2 and 3 with the condition that the digit 2 occurs twice in each number is

Options

  1. A7C225{ }^7 C_2 2^5
  2. B7p225{ }^7 p_2 2^5
  3. C7C252{ }^7 C_2 5^2
  4. DNone of these

Correct answer

A. 7C225{ }^7 C_2 2^5

Step-by-step solution

Other than 2, remaining five places can be filled by 1 and 3 for each place. The number of ways for five places is 2×2×2×2×2=252 \times 2 \times 2 \times 2 \times 2=2^5. For 2 , selecting 2 places out of 7 is 7C2{ }^7 C_2. Hence, the required number of ways is 7C2×25{ }^7 C_2 \times 2^5.
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