In how many ways can a committee of 5 made out 6 men and 4 women containing atleast one woman?

Step-by-step solution

A committee of 5 out of 6+4=10 can be made in ¹⁰ C ₅=252 ways. If no woman is to be included, thennumber of ways = ⁵ C ₅=6 the required number =252-6=246