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BITSAT 2014
Exam
BITSAT
Year
2014
Subject
Mathematics
Chapter
Permutation and Combination

BITSAT 2014 · Mathematics · Permutation and Combination

In how many ways can a committee of 5 made out 6 men and 4 women...

In how many ways can a committee of 5 made out 6 men and 4 women containing atleast one woman?

Options

  1. A246
  2. B222
  3. C186
  4. DNone of these

Correct answer

A. 246

Step-by-step solution

A committee of 5 out of 6+4=106+4=10 can be made in 10C5=252{ }^{10} \mathrm{C}_{5}=252 ways. If no woman is to be included, thennumber of ways =5C5=6∴={ }^{5} \mathrm{C}_{5}=6\therefore the required number =252−6=246=252-6=246
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