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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Mathematics
Chapter
Permutation and Combination

BITSAT 2013 · Mathematics · Permutation and Combination

In how many ways can 5 boys and 5 girls be seated at a round table...

In how many ways can 5 boys and 5 girls be seated at a round table so that no two girls may be together?

Options

  1. A4!4 !
  2. B5!5 !
  3. C4!+5!4 !+5 !
  4. D4!×5!4 ! \times 5 !

Correct answer

D. 4!×5!4 ! \times 5 !

Step-by-step solution

Leaving one seat vacant between two boys, 5 boys may be seated in 4!4 ! ways. Then at remaining 5 seats, 5 girls any sit in 5!5 ! ways. Hence the required number =4!×5!=4 ! \times 5 !
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