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BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Mathematics
Chapter
Permutation and Combination

BITSAT 2012 · Mathematics · Permutation and Combination

In how many ways can 5 prizes be distributed among 4 boys when...

In how many ways can 5 prizes be distributed among 4 boys when every boy can take one or more prizes?

Options

  1. A1024
  2. B625
  3. C120
  4. D600

Correct answer

A. 1024

Step-by-step solution

First prize may be given to any one of the 4 boys, hence first prize can be distributed in 4 ways. similarly every one of second, third, fourth and fifth prizes can also be given in 4 ways. the number of ways of their distribution =4×4×4×4×4=45=1024=4 \times 4 \times 4 \times 4 \times 4=4^{5}=1024
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