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BITSAT 2011
Exam
BITSAT
Year
2011
Subject
Mathematics
Chapter
Permutation and Combination

BITSAT 2011 · Mathematics · Permutation and Combination

If ( ^ 20 C_ r = ^ 20 C_ r-10 ) then ( ^ 18 C_ r ) is equal to

If ({ }^{20} Cr=20Cr−10\mathrm{C}_{\mathrm{r}}={ }^{20} \mathrm{C}_{\mathrm{r}-10}) then ({ }^{18} Cr\mathrm{C}_{\mathrm{r}}) is equal to

Options

  1. A4896
  2. B816
  3. C1632
  4. DNone of these

Correct answer

B. 816

Step-by-step solution

({ }^{20} Cr=20Cr−10⇒r+(r−\mathrm{C}_{\mathrm{r}}={ }^{20} \mathrm{C}_{\mathrm{r}-10} \Rightarrow \mathrm{r}+(\mathrm{r}-10)=20 \Rightarrow r=\mathrm{r}=15) (\therefore \quad{ }^{18} Cr=18C15=18\m\mathrm{C}_{\mathrm{r}}={ }^{18} \mathrm{C}_{15}={ }^{18} \mmmathrm{C}}_{3}=\frac{18 \cdot17 \cdot16}{1 \cdot2 \cdot3}=816)
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