Initially spring is in natural length and both the blocks are in rest condition. Then determine the maximum extension in the spring. K=20 ~N ~m ⁻¹

Step-by-step solution

a= F m₁+m₂ By work - energy theorem aligned & (F-m₁ a ) x₁+ (m₂ a ) x₂- 1 2 K (x₁+x₂ )^2=0 & m₂ F m₁+m₂ (x₁+x₂ )= K 2 (x₁+x₂ )^2 & (x₁+x₂ )=m₂ F m₁+m₂ 2 k & = 1 1 1.5 2 20 = 1 15 m= 100 15 ~cm = 20 3 ~cm aligned