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AIIMS 201926 May

Exam: AIIMS
Year: 2019
Date: 26 May
Subject: Physics
Chapter: Work, Power and Energy

AIIMS 2019 · 26 May · Physics · Work, Power and Energy

Initially spring is in its natural length. Now block of mass 0.25...

Initially spring is in its natural length. Now block of mass

0.25 \mathrm{~kg}

is released, then find out maximum force by system on the floor. Initially spring is in its natural length. Now block of mass 0.25 ~kg is released, then find out maximum force by

Initially spring is in its natural length. Now block of mass 0.25 ~kg is released, then find out maximum force by

Options

A $15 \mathrm{~N}$
B $20 \mathrm{~N}$
C $25 \mathrm{~N}$
D $30 \mathrm{~N}$

Correct answer

C. $25 \mathrm{~N}$

Step-by-step solution

By using work - energy theory on

(0.25) \mathrm{kg}

\begin{aligned} & \frac{1}{2} k x^2=m g x, \text{ where } m=2 \mathrm{ kg} \\ & k x=2 m g=2 \times 0.25 \times 10=5 \mathrm{ N} \\ & N=k x+2 \times 10=5+20=25 \mathrm{ N}\end{aligned}

$$

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