Initially spring is in its natural length. Now block of mass 0.25 ~kg is released, then find out maximum force by system on the floor.

Step-by-step solution

By using work - energy theory on (0.25) kg aligned & 1 2 k x^2=m g x, where m=2 ~kg & k x=2 m g=2 0.25 10=5 ~N & N=k x+2 10=5+20=25 ~N aligned